A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point)
Responses
28 kg⋅m/s
28 kilograms times meters per second
7,000 kg⋅m/s
7,000 kilograms times meters per second
70,000 kg⋅m/s
70,000 kilograms times meters per second
280 kg⋅m/s
280 kilograms times meters per second
To find the impulse, we can use the equation:
Impulse = Force * Time
Substituting the given values, we have:
Impulse = 1,400 N * 0.02 s = 28 N⋅s = 28 kg⋅m/s
Therefore, the impulse of this punch is 28 kg⋅m/s.