Calculate the difference (subtract) in electronegativities for each set of elements below. Use the difference to determine the type of bond that will form (Use the chart above).
Column A
1.
Nitrogen (N) and Fluorine (F) in NF3.
Column B
a.The electronegativity difference is 1. The bond will be polar covalent.
b.The electronegativity difference is 0. The bond will be nonpolar covalent.
c.The electronegativity difference is 1. The bond will be nonpolar covalent.
d.The electronegativity difference is 2.0. The bond will be ionic.
e.The electronegativity difference is 0. The bond will be ionic.
f.The electronegativity difference is 2.0. The bond will be polar covalent.
The electronegativity difference between Nitrogen (N) and Fluorine (F) in NF3 is 1.
According to the chart above, the bond will be polar covalent.
The correct answer is option a. The electronegativity difference is 1. The bond will be polar covalent.