Let z=-3+ 2i
Find r and Q.Draw the angle Q and leave your answer in polar form
To find r (the magnitude of z), we use the formula r = √(a^2 + b^2), where a = -3 and b = 2 in this case:
r = √((-3)^2 + 2^2) = √(9 + 4) = √13
To find Q (the angle), we use the formula tan(Q) = b/a, where a = -3 and b = 2 in this case:
Q = arctan(2/-3) ≈ -33.69°
Therefore, in polar form, z = (√13, -33.69°)