Given ABC≅DEF,m<A=2x+5,and m<D=3x+2, find m<A
A. 10
B. 22
C. 11
D. 3
If ABC≅DEF, then the corresponding angles are congruent. Therefore, we have:
m<A = m<D
2x + 5 = 3x + 2
2x - 3x = 2 - 5
-x = -3
x = 3
Substitute x = 3 back into the equation to find m<A:
m<A = 2x + 5 = 2(3) + 5 = 11
Therefore, the answer is C. 11.