KOH + F2 -> KF + F2O + H2O
The given chemical equation is:
2 KOH + F2 → 2 KF + F2O + H2O
This reaction shows the combination of potassium hydroxide (KOH) and fluorine gas (F2) to produce potassium fluoride (KF), oxygen difluoride (F2O), and water (H2O).
Here's a breakdown of the reaction:
2 KOH + F2 → 2 KF + F2O + H2O
This equation indicates that two molecules of potassium hydroxide (KOH) are reacting with one molecule of fluorine gas (F2). On the left side, there are two potassium (K) atoms, two oxygen (O) atoms, and two hydrogen (H) atoms. On the right side, there are two potassium (K) atoms, two fluorine (F) atoms, one oxygen (O) atom, and two hydrogen (H) atoms.
Balancing the equation:
To balance the equation, we can observe that there are already two potassium (K) atoms on both sides of the equation, two oxygen (O) atoms on both sides, and two hydrogen (H) atoms on both sides. Hence, these elements are balanced. We now need to balance the fluorine (F) atoms.
Since there are two fluorine atoms on the left side, we need to have two molecules of fluorine gas on the right side to balance it.
The balanced equation becomes:
2 KOH + F2 → 2 KF + F2O + H2O
Now, both sides have a total of two potassium (K) atoms, two fluorine (F) atoms, two oxygen (O) atoms, and two hydrogen (H) atoms, making it a balanced equation.