expand the binomial-

(4y-7)^4

Expanding the binomial (4y-7)^4 using the Binomial Theorem, we have:

(4y-7)^4 = C(4,0) * (4y)^4 * (-7)^0 + C(4,1) * (4y)^3 * (-7)^1 + C(4,2) * (4y)^2 * (-7)^2 + C(4,3) * (4y)^1 * (-7)^3 + C(4,4) * (4y)^0 * (-7)^4

= 1 * (4y)^4 * 1 + 4 * (4y)^3 * (-7) + 6 * (4y)^2 * 49 + 4 * (4y)^1 * (-343) + 1 * (4y)^0 * 2401

Simplifying further:

= 256y^4 + 4*64y^3*(-7) + 6*16y^2*49 + 4*4y*(-343) + 1*1*2401

= 256y^4 - 896y^3 + 5888y^2 - 1372y + 2401

Therefore, the expanded form of (4y-7)^4 is 256y^4 - 896y^3 + 5888y^2 - 1372y + 2401.