when you count by one from many intergers, you are counting consecutive integer. Using variable, the consecutive intergers are n, n+ 1 and n + 2. The sum of the the consecutive integers is 48. What are the integers?
Let's assume that the first integer is represented by the variable 'n'.
According to the given information, the consecutive integers are n, n+1, and n+2.
To find the sum of the consecutive integers, we can add them together:
n + (n+1) + (n+2) = 48
Simplifying the equation by combining like terms:
3n + 3 = 48
Subtracting 3 from both sides of the equation:
3n = 45
Dividing both sides of the equation by 3:
n = 15
So the first integer is 15.
The second integer is n+1 = 15+1 = 16.
The third integer is n+2 = 15+2 = 17.
Therefore, the three consecutive integers that have a sum of 48 are 15, 16, and 17.