Use the method of your choice to determine the following probability.
Drawing at least one ten when you draw a card from a standard deck 8 times (replacing the card each time you draw)
To determine the probability of drawing at least one ten when drawing a card from a standard deck 8 times with replacement, we can use the concept of complementary probability.
The complementary probability is the probability of the event not occurring. In this case, the event not occurring would mean not drawing any tens in the 8 draws.
The probability of drawing a ten in a single draw from a standard deck (with replacement) is 4/52, since there are 4 tens out of a total of 52 cards.
So, the probability of not drawing a ten in a single draw is 1 - 4/52 = 48/52.
Since we are drawing 8 times with replacement, the probability of not drawing a ten in any of the 8 draws is (48/52)^8.
Therefore, the probability of drawing at least one ten in 8 draws is 1 - (48/52)^8 ≈ 0.7278, or approximately 72.78%.