A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are randomly selected if the first selection is
replaced before the second is made.
Since the first selection is replaced before the second is made, the probability of selecting a good coil on the first draw is 88/100 = 44/50 = 22/25.
Since the first selection is replaced before the second is made, the probability of selecting a good coil on the second draw is also 88/100 = 44/50 = 22/25.
Since the selections are independent events, the probability of both events occurring (i.e., selecting two good coils) is the product of their individual probabilities: (22/25) * (22/25) = 484/625.
Therefore, the probability of getting two good coils when two coils are randomly selected (with replacement) is 484/625.