What is the surface area of a square pyramid where the base edge is 8 ft. and the slant height is 16 ft.?(1 point)
Responses
512 ft.2512 ft. squared
320 ft.2
320 ft. squared
128 ft.2
128 ft. squared
256 ft.2
To find the surface area of a square pyramid, you need to find the area of the base and the area of the four triangular faces.
The area of the base is simply the length of one side squared. In this case, the base edge is 8 ft, so the area of the base is 8^2 = 64 sq. ft.
The area of each triangular face can be found using the formula A = 1/2 * base * height. In this case, the base is the base edge of the pyramid (8 ft) and the height is the slant height (16 ft). So, the area of each triangular face is 1/2 * 8 * 16 = 64 sq. ft.
Since there are four triangular faces, the total area of the four triangular faces is 4 * 64 = 256 sq. ft.
To find the total surface area, you add the area of the base and the total area of the four triangular faces:
Total Surface Area = Area of Base + Total Area of Triangular Faces
= 64 + 256
= 320 sq. ft.
Therefore, the correct answer is 320 ft.2 or 320 ft. squared.