Give the slope of y - 3 = 4 (x+8) and a point on the line.
A. the slope is 4 and (8, -3) is on the line.
B. the slope is 4 and (-8, 3) is on the line.
C. the slope is 3 and (-8, 4) is on the line.
D. the slope is 8 and (3, 4) in on the line.
The given equation is in the form y - y₁ = m(x - x₁), where m represents the slope and (x₁, y₁) represents a point on the line.
Comparing the given equation to this form, we can see that y₁ = 3 - 3 = 0 and x₁ = -8.
Therefore, using the slope-intercept form, y = mx + b, we can rewrite the equation as y = 4x + 32.
The slope of the line is 4.
Now, let's plug in the values for x = 8 and y = -3 into the equation y = 4x + 32:
-3 = 4(8) + 32
-3 = 32 + 32
-3 = 64
As -3 does not equal 64, the point (8, -3) is not on the line.
Therefore, the correct answer is:
B. the slope is 4 and (-8, 3) is on the line.