Evaluate the function f(x)=−sinx
at x=3π2
.(1 point)
(3π2
,
)
To evaluate the function f(x) = -sin(x) at x = 3π/2, we substitute 3π/2 for x in the function:
f(3π/2) = -sin(3π/2)
Since sin(3π/2) = -1, we have:
f(3π/2) = -(-1)
Simplifying, we get:
f(3π/2) = 1
Therefore, f(3π/2) = 1.