No need of explanation !!
7. On a user's manual of a motorbike you see a specification labeled as "the bike can accelerate to 100km/h from rest in 7 4seconds A) what can you say about the maximum average acceleration of the bike?
B) How far does it travel in this time?
8. The angle bbetween vector A and Vector B is 20⁰. If the magnitude of vector A is 6 unite and that B is 4 units.
What is the component of vectors along the direction of vector B.
9. A girl pushes a box placed in the floor with a force of 50N at an angle of 37⁰ below the horizontal. If the box moves towards the positive x direction. What are the vector components of the force?
A) The maximum average acceleration of the bike can be determined by using the formula: average acceleration = change in velocity / time taken. In this case, the change in velocity is 100 km/h (or 27.78 m/s, converting km/h to m/s) and the time taken is 7.4 seconds. So, the average acceleration would be 27.78 m/s / 7.4 s = 3.75 m/s^2.
B) To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 0 m/s (as it starts from rest), the acceleration is the average acceleration calculated in part A (3.75 m/s^2), and the time is 7.4 seconds. Plugging these values into the formula, we get: distance = 0 * 7.4 + 0.5 * 3.75 * (7.4)^2 = 81.825 meters.
8. To find the component of vector A along the direction of vector B, we need to use the formula: component of A along B = magnitude of A * cos(angle between A and B). In this case, the magnitude of vector A is 6 units and the angle between A and B is 20 degrees. Plugging these values into the formula, we get: component of A along B = 6 * cos(20) = 5.686 units.
9. The vector components of the force can be found by using trigonometry. Since the force is at an angle of 37 degrees below the horizontal, we can split it into its horizontal and vertical components.
The horizontal component of the force (F_x) can be found using the formula: F_x = F * cos(angle). In this case, the force is 50N and the angle is 37 degrees. Plugging these values into the formula, we get: F_x = 50 * cos(37) = 39.83 N.
The vertical component of the force (F_y) can be found using the formula: F_y = F * sin(angle). In this case, the force is 50N and the angle is 37 degrees. Plugging these values into the formula, we get: F_y = 50 * sin(37) = 30.29 N.