In triangle, J, K, L, comma△JKL, start overline, L, J, end overline, \cong, start overline, K, L, end overline
LJ
≅
KL
and m, angle, K, equals, 10, degrees, .m∠K=10
∘
. Find m, angle, J, .m∠J
The information provided states that ∠KLJ ≅ ∠K and m∠K = 10°.
Since ∠KLJ ≅ ∠K, it means that ∠KLJ is also 10°.
Therefore, m∠J = m∠KLJ = 10°.