There are two different vats. The first vat has 12 gallons is being filled at a rate of 2 gallons per minute. The second car has 120 gallons and is leaking fluid at a rate of 6 gallons per minute. After how many seconds will both gate have the same amount of liquid
To find the time it takes for both vats to have the same amount of liquid, we need to set up an equation and solve for time.
Let's represent the time in seconds as 't'.
At t seconds, the first vat will have 12 + 2t gallons of liquid.
And the second vat will have 120 - 6t gallons of liquid.
To find when both vats have the same amount of liquid, we can set up the equation:
12 + 2t = 120 - 6t
Simplifying the equation:
2t + 6t = 120 - 12
8t = 108
Dividing both sides by 8:
t = 108/8
t = 13.5 seconds
Therefore, after 13.5 seconds, both vats will have the same amount of liquid.