(3^4)^2 . 3^-5

show ur work

To solve this expression, we must first simplify the exponents separately before multiplying the results.

1) Simplifying the first exponent:

(3^4)^2 = 3^(4*2) = 3^8

2) Simplifying the second exponent:

3^-5 = 1/(3^5)

Now we can multiply the results:

(3^4)^2 . 3^-5 = 3^8 . 1/(3^5)

Since the bases are the same (3), we can subtract the exponents:

= 3^(8-5) = 3^3 = 27

Therefore, (3^4)^2 . 3^-5 is equal to 27.