(3^4)^2 . 3^-5
show ur work
To solve this expression, we must first simplify the exponents separately before multiplying the results.
1) Simplifying the first exponent:
(3^4)^2 = 3^(4*2) = 3^8
2) Simplifying the second exponent:
3^-5 = 1/(3^5)
Now we can multiply the results:
(3^4)^2 . 3^-5 = 3^8 . 1/(3^5)
Since the bases are the same (3), we can subtract the exponents:
= 3^(8-5) = 3^3 = 27
Therefore, (3^4)^2 . 3^-5 is equal to 27.