What is the surface area of a square pyramid where the base edge is 8 ft. and the slant height is 16 ft.?(1 point)
Responses
320 ft.2
320 ft. squared
512 ft.2512 ft. squared
128 ft.2
128 ft. squared
256 ft.2
To find the surface area of a square pyramid, you need to calculate the areas of the base and the four triangular faces.
The area of the base can be found by squaring the length of one of the sides. In this case, the base edge is 8 ft, so the area of the base is 8 ft * 8 ft = 64 ft².
The area of each triangular face can be found using the formula: 0.5 * base * height. Here, the base of each triangular face is the base edge of the pyramid (8 ft), and the height is the slant height (16 ft). So the area of each triangular face is 0.5 * 8 ft * 16 ft = 64 ft².
Since there are 4 triangular faces, the total area of the triangular faces is 4 * 64 ft² = 256 ft².
To find the total surface area of the pyramid, you add the area of the base to the total area of the triangular faces: 64 ft² + 256 ft² = 320 ft².
So the surface area of the square pyramid is 320 ft².