Solve the system of equations
15x+31y=-3
X=-y+3
X=
Y=
To find x and y, we substitute the value of x from the second equation into the first equation:
15(-y+3) + 31y = -3
Simplifying this equation gives us:
-15y + 45 + 31y = -3
Combine like terms:
16y + 45 = -3
Then, subtract 45 from both sides:
16y = -48
Divide both sides by 16:
y = -3
Now that we have a value for y, we can substitute it back into either of the original equations to solve for x. Using the second equation:
x = -y + 3
x = -(-3) + 3
x = 3 + 3
x = 6
Therefore, the solution to the system of equations is:
x = 6
y = -3