Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. The first step to solving this problem algebraically is to write an equation: 3(x+x−3)=75
, where x
represents the cost of an adult ticket. Identify the next step, which would simplify the equation before solving for the variable. (1 point)
Responses
Combine like terms in parentheses.
Combine like terms in parentheses.
Distribute values over the variables.
Distribute values over the variables.
Divide 75 by 3.
Divide 75 by 3.
Add 3 to 75
Combine like terms in parentheses.
Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. Find the price of each ticket.(1 point)
Responses
an adult ticket is $14 and a child ticket is $11
an adult ticket is $14 and a child ticket is $11
an adult ticket is $8 and a child ticket is $5
an adult ticket is $8 and a child ticket is $5
an adult ticket is $11 and a child ticket is $8
an adult ticket is $11 and a child ticket is $8
an adult ticket is $12.50 and a child ticket is $9.50
an adult ticket is $12.50 and a child ticket is $9.50
an adult ticket is $12.50 and a child ticket is $9.50
Three adult and three child movie tickets were purchased for $75. The cost of each child ticket is $3 less than the cost of an adult ticket. Identify the first step if solving this problem arithmetically, which would find the cost of one adult and one child ticket. (1 point)
Responses
Divide 75 by 3.
Divide 75 by 3.
Add 3 to 75.
Add 3 to 75.
Subtract 6 from 75.
Subtract 6 from 75.
Divide 75 by 6.
Divide 75 by 6.