What is the value of`(-3i)(4i)`?
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To find the value of `(-3i)(4i)`, we can use the property of multiplication that states the product of two imaginary numbers is equal to the product of their coefficients multiplied by -1.
Given that i^2 = -1, we can substitute the value into the expression:
(-3i)(4i)
= (-3 * 4)(i * i)
= -12(i * i)
Since i * i = i^2 = -1:
= -12(-1)
= 12
Therefore, the value of `(-3i)(4i)` is 12.