Sue is wrapping books to give as gifts book a has a length of 6.5 in and width of 1 in and has a height of 8.5 in book b has a length of 5.5 in a width of 2 in and a height of 8 in based on the surface area which book will require less wrapping paper
To calculate the surface area of each book, we will find the area of each side and then add them up.
For book A:
- The area of the front and back sides is equal to the length multiplied by the height: 6.5 in * 8.5 in = 55.25 square inches
- The area of the two smaller sides is equal to the width multiplied by the height: 2 * (1 in * 8.5 in) = 17 square inches
- The area of the top and bottom sides is equal to the length multiplied by the width: 6.5 in * 1 in = 6.5 square inches
Adding up all the areas, the surface area of book A is: 55.25 sq in + 17 sq in + 6.5 sq in = 78.75 square inches
For book B:
- The area of the front and back sides is equal to the length multiplied by the height: 5.5 in * 8 in = 44 square inches
- The area of the two smaller sides is equal to the width multiplied by the height: 2 * (2 in * 8 in) = 32 square inches
- The area of the top and bottom sides is equal to the length multiplied by the width: 5.5 in * 2 in = 11 square inches
Adding up all the areas, the surface area of book B is: 44 sq in + 32 sq in + 11 sq in = 87 square inches
Therefore, book A will require less wrapping paper as it has a smaller surface area than book B.