The sum of three consecutive numbers is 72. What is the largest of these numbers? (1 point)

23
25
26
28

Let's call the smallest number x. The next consecutive number would be x + 1, and the one after that would be x + 2.

According to the problem, the sum of these three numbers is 72. So, we can set up the equation:
x + (x + 1) + (x + 2) = 72
3x + 3 = 72
Subtracting 3 from both sides gives:
3x = 69
Dividing both sides by 3 gives:
x = 23
Therefore, the largest of the three numbers is x + 2 = 23 + 2 = 25.
The answer is 25.