Solve the compound inequality 5x+11≥−9 and 10x−3≤27
To solve 5x + 11 ≥ -9, we need to isolate x.
Subtracting 11 from both sides of the inequality, we get:
5x ≥ -20
To solve 10x - 3 ≤ 27, we need to isolate x.
Adding 3 to both sides of the inequality, we get:
10x ≤ 30
Now we can solve for x in both inequalities.
For 5x ≥ -20:
Dividing both sides by 5, we get:
x ≥ -4
For 10x ≤ 30:
Dividing both sides by 10, we get:
x ≤ 3
Therefore, the solution to the compound inequality is -4 ≤ x ≤ 3.