Write an equation in standard form of an ellipse that is 50 units high and 40 units wide. The center of the ellipse is (0, 0)
The standard form equation of an ellipse is $\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1$, where $(0,0)$ represents the center of the ellipse and $a$ and $b$ represent the lengths of half of the major and minor axes respectively.
In this case, the ellipse has a height of 50 units, so $a = \dfrac{50}{2} = 25$. The ellipse has a width of 40 units, so $b = \dfrac{40}{2} = 20$.
Substituting these values into the standard form equation, we have $\dfrac{x^2}{25^2} + \dfrac{y^2}{20^2} = 1$.
Simplifying, we get $\dfrac{x^2}{625} + \dfrac{y^2}{400} = 1$.
Therefore, the equation in standard form of the given ellipse is $\boxed{\dfrac{x^2}{625} + \dfrac{y^2}{400} = 1}$.