A ball weighs 1.5 pounds, and I drop it from 5 meters up in the air, how long would it take for it to hit the ground?
To determine the time it takes for the ball to hit the ground, we can use the equation for free fall motion:
h = (1/2) * g * t^2
Where:
h = height (given as 5 meters)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
Rearranging the equation, we get:
t^2 = (2 * h) / g
Substituting the given values:
t^2 = (2 * 5) / 9.8
t^2 ≈ 1.02
Taking the square root of both sides:
t ≈ √1.02
t ≈ 1.01 seconds
Therefore, it would take approximately 1.01 seconds for the ball to hit the ground.
A balled up paper weighs 0.3 pounds, and I drop it from 5 meters up in the air, how long would it take for it to hit the ground?
Just like the previous question, we can use the equation for free fall motion:
h = (1/2) * g * t^2
Where:
h = height (given as 5 meters)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
Since the weight of the balled up paper is given as 0.3 pounds, it doesn't directly affect the time it takes for the paper to fall.
Using the same calculation as before:
t^2 = (2 * 5) / 9.8
t^2 ≈ 1.02
Taking the square root of both sides:
t ≈ √1.02
t ≈ 1.01 seconds
Therefore, it would also take approximately 1.01 seconds for the balled up paper to hit the ground. In this case, the weight of the object does not impact the time of descent as long as other conditions (such as air resistance) are negligible.