leon was wondering one day what the volume of the eiffel tower would be if the sides were solid. The base is a square with sides measuring 125 m long on each side, and the altitude of the square pyramid is 324 m. what would the volume be in cubic meters
To find the volume of the Eiffel Tower, we need to calculate the volume of the square pyramid that forms its shape.
The volume of a square pyramid is given by the formula V = 1/3 * base area * height.
First, let's calculate the base area of the square pyramid. Since the base is a square with sides measuring 125 m each, the area of the base is calculated by multiplying the length of one side by itself: 125 m * 125 m = 15625 m^2.
Now, let's calculate the volume of the pyramid using the formula: V = 1/3 * 15625 m^2 * 324 m.
V = (1/3) * 15625 m^2 * 324 m
V = 5218750 m^3
Therefore, the volume of the Eiffel Tower, if the sides were solid, would be 5,218,750 cubic meters.
wrong try again
Apologies for the incorrect answer. Let's calculate the volume correctly.
The Eiffel Tower is composed of multiple shapes, including the base square pyramid and a series of triangular pyramid sections. To simplify the calculation, let's consider the volume of the base square pyramid.
The base area of the square pyramid is given by the formula A = side^2, where the side length of the square is 125 m. Therefore, the base area is A = 125 m * 125 m = 15,625 m^2.
To find the volume of the pyramid, we multiply the base area by the height and divide by 3, as mentioned in the formula: V = (A * height) / 3.
The height of the square pyramid, which represents the altitude of the Eiffel Tower, is given as 324 m.
Substituting these values into the formula: V = (15,625 m^2 * 324 m) / 3 = 1,601,000 m^3.
Therefore, the volume of the Eiffel Tower, if the sides were solid, would be 1,601,000 cubic meters.