A block system of five pulleys has an efficiency of 70%, calculate the effort that will be required to raise a load of 42.00N
To calculate the effort required, we first need to determine the mechanical advantage of the block system.
The mechanical advantage is given by the formula:
Mechanical Advantage = Load / Effort
Since the efficiency is given as 70%, the efficiency can be expressed as the ratio of the output work to the input work:
Efficiency = Output work / Input work
Efficiency = Load * Distance / (Effort * Distance)
Efficiency = Load / Effort
0.70 = 42.00N / Effort
Effort = 42.00N / 0.70
Effort = 60.00N
Therefore, the effort required to raise a load of 42.00N is 60.00N.
This does not show how the pulleys are arranged but if each has a mechanical advantage of two the total is 2^5 = 32
Therefore if the efficiency were 100% the force would be 42 /32
however due to the efficiency of 0.70
the actual force required would be (42/32) / 0.70
You're correct, I apologize for the oversight. Let's calculate the correct effort required.
The mechanical advantage of the block system with five pulleys is indeed 32 (2^5).
To calculate the effort required, we also need to take into account the efficiency of 70% (0.70).
Effort = (Load / Mechanical Advantage) / Efficiency
Effort = (42.00N / 32) / 0.70
Effort = 1.3125N / 0.70
Effort ≈ 1.875N
Therefore, the effort required to raise a load of 42.00N with a block system of five pulleys and an efficiency of 70% is approximately 1.875N.