How many grams of HCI are produced when 6.9 kg C12H4CI6 react?
To determine the number of grams of HCI produced when 6.9 kg of C12H4CI6 reacts, we need to use the balanced chemical equation for the reaction.
The balanced equation for the reaction of C12H4CI6 is:
C12H4CI6 + 12 H2O -> 12 HCI + 13 CO2
From the balanced equation, we can see that every 1 mol of C12H4CI6 produces 12 mol of HCI. To find the number of moles of C12H4CI6, we need to convert the given mass to moles using the molar mass of C12H4CI6.
The molar mass of C12H4CI6 is calculated as follows:
12 C: 12 (atomic mass of carbon) = 12 g/mol
4 H: 4 (atomic mass of hydrogen) = 4 g/mol
1 Cl: 1 (atomic mass of chlorine) = 1 g/mol
6 I: 6 (atomic mass of iodine) = 6 g/mol
Total molar mass of C12H4CI6 = 12 + 4 + 1 + 6 = 23 g/mol
Now, we can calculate the number of moles of C12H4CI6:
Moles of C12H4CI6 = mass / molar mass
= 6.9 kg * 1000 g/kg / 23 g/mol
= 300 g / 23 g/mol
= 13.04 mol
Since every 1 mol of C12H4CI6 produces 12 mol of HCI, we can calculate the number of moles of HCI produced:
Moles of HCI = Moles of C12H4CI6 * (12 mol HCI / 1 mol C12H4CI6)
= 13.04 mol * (12 mol HCI / 1 mol C12H4CI6)
= 156.48 mol
Lastly, to convert moles of HCI to grams, we multiply by the molar mass of HCI. The molar mass of HCI is obtained from the periodic table as follows: 1 H: 1 g/mol + 1 Cl: 35.5 g/mol = 36.5 g/mol.
Therefore, the mass of HCI produced is:
Mass of HCI = Moles of HCI * Molar mass of HCI
= 156.48 mol * 36.5 g/mol
= 5707.28 g
Thus, 6.9 kg of C12H4CI6 will produce 5707.28 grams of HCI.