How many molecules are in 75 L of F2 SATP
To determine the number of molecules in 75 L of F2 at SATP (Standard Ambient Temperature and Pressure) conditions, we can use the ideal gas law equation.
The ideal gas law equation is: PV = nRT
Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L•atm/mol•K)
T = temperature (in Kelvin)
SATP conditions are defined as 298 K (25 °C) and 1 atm of pressure.
We can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
Given:
V = 75 L
P = 1 atm
T = 298 K
Substituting these values into the equation:
n = (1 atm * 75 L) / (0.0821 L•atm/mol•K * 298 K)
Performing the calculation:
n = 75 / (0.0821 * 298)
n ≈ 3.213
Therefore, there are approximately 3.213 moles of F2 in 75 L at SATP conditions.
To convert moles to molecules, we use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.
Number of molecules = number of moles * Avogadro's number
Number of molecules = 3.213 mol * 6.022 x 10^23 molecules/mol
Number of molecules ≈ 1.936 x 10^24 molecules
Therefore, there are approximately 1.936 x 10^24 molecules in 75 L of F2 at SATP.