A side of the triangle below has been extended to form an exterior angle of 125°. Find the value of xx.
Since the exterior angle is equal to the sum of the two remote interior angles, we have $180^\circ = x + 125^\circ$, which implies $x=\boxed{55^\circ}$. [asy]
pair A,B,C;
A=(0,0);
B=(80,0);
C=(30,50);
draw(A--B--C--cycle);
label("x",C,N);
label("80",B,SE);
label("75",C,NW);
draw(C--(70,0),dashed);
[/asy]
Idiot
I apologize if my response was not clear or if it did not meet your expectations. If you have any further questions or need further clarification, please let me know and I will be happy to assist you.
To find the value of xx, we need to understand the relationship between exterior angles and the corresponding interior angles of a triangle.
In a triangle, the sum of the measures of the three interior angles is always equal to 180 degrees.
In this case, the exterior angle formed by extending one of the sides of the triangle is 125 degrees.
The measure of an exterior angle is equal to the sum of the measures of the two interior angles opposite to it.
So, we can set up the equation:
125° = x + x
125° = 2x
To solve for xx, we divide both sides of the equation by 2:
125° ÷ 2 = 2x ÷ 2
62.5° = x
Therefore, the value of xx in this triangle is 62.5 degrees.