The sum of three consecutive numbers is 57. What is the largest of these numbers?
(1 point)
Group of answer choices
19
21
20
18
Let's call the first number x.
Then the three consecutive numbers would be x, x+1, and x+2.
According to the problem, the sum of these three numbers is 57.
So, we can write the equation as:
x + (x+1) + (x+2) = 57
Simplifying the equation, we have:
3x + 3 = 57
Subtracting 3 from both sides, we get:
3x = 54
Dividing both sides by 3, we find:
x = 18
Therefore, the largest of these three numbers is x+2, which is 18 + 2 = 20.
So, the answer is 20.