At its peak, a tornado is 60m in diameter and carries 500 km/h winds. What is its angular velocity in rev/sec?
To find the angular velocity of the tornado in rev/sec, we need to find the number of revolutions per second by dividing the speed of the tornado by the circumference of the tornado.
First, let's find the circumference of the tornado.
Circumference = π * diameter
Circumference = π * 60m
Next, let's convert the speed of the tornado from km/h to m/s, as the units need to be consistent.
Speed = 500 km/h * (1000 m/1 km) * (1 h/3600 s)
Speed = 500 * 1000 / 3600 m/s
Now we can find the angular velocity.
Angular velocity = Speed / Circumference
Angular velocity = (500 * 1000 / 3600) m/s / (π * 60m)
Angular velocity ≈ 8.726 π rad/s
Finally, we convert from radians to revolutions by dividing by 2π.
Angular velocity in rev/sec ≈ (8.726 π rad/s) / (2π)
Angular velocity in rev/sec ≈ 8.726 / 2
Angular velocity in rev/sec ≈ 4.363 rev/sec
Therefore, the angular velocity of the tornado is approximately 4.363 rev/sec.