Divide.
Write your answer in simplest form.
\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = {?} \]
Apologies for the mistake, let's correct it. To divide fractions, we multiply the first fraction by the reciprocal (flipped) of the second fraction.
So, we have:
\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = -\dfrac{6}{7} \times \left(-\dfrac{8}{3}\right) \]
Multiplying the numerators and denominators, we get:
\[ -\dfrac{6 \times (-8)}{7 \times 3} = \dfrac{48}{21} \]
Next, we can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3:
\[ \dfrac{48}{21} = \dfrac{16}{7} \]
Therefore, \[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = \dfrac{16}{7} \]
To divide fractions, we multiply the first fraction by the reciprocal (flipped) of the second fraction.
So, we have:
\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = -\dfrac{6}{7} \times \dfrac{-8}{3} \]
We can simplify this expression by canceling out common factors.
The 6 in the numerator and the 8 in the denominator can both be divided by 2:
\[ -\dfrac{6}{7} \times \dfrac{-8}{3} = -\dfrac{3}{7} \times \dfrac{-4}{1} \]
Now, we can multiply:
\[ -\dfrac{3}{7} \times \dfrac{-4}{1} = \dfrac{12}{7} \]
Therefore, \[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = \dfrac{12}{7} \]
wrong. you are really screwing with my grades.
To divide two fractions, we multiply the first fraction by the reciprocal of the second fraction. The reciprocal of a fraction is obtained by interchanging the numerator and denominator.
In this case, we have \(\frac{-6}{7}\) divided by \(\left(-\frac{3}{8}\right)\). To find the solution, we need to multiply the first fraction by the reciprocal of the second fraction.
The reciprocal of \(-\frac{3}{8}\) is \(-\frac{8}{3}\). So, we rewrite the division expression as multiplication:
\(\frac{-6}{7} \times \left(-\frac{8}{3}\right)\)
Now, we can multiply numerators together and denominators together:
\(\frac{(-6) \times (-8)}{7 \times 3}\)
Simplifying further:
\(\frac{48}{21}\)
To write the answer in simplest form, we need to find the greatest common divisor (GCD) of 48 and 21, and divide both the numerator and denominator by it.
The GCD of 48 and 21 is 3. By dividing both numerator and denominator by 3, we get:
\(\frac{48 \div 3}{21 \div 3} = \frac{16}{7}\)
So, \(\frac{-6}{7} \div \left(-\frac{3}{8}\right)\) simplifies to \(\frac{16}{7}\).