Two kids are standing twnty feet away from each other when they start to run in opposite directions at, one running at the speed of 180 feet per minute and the other running at the speed of 120 feet per minute. How many minutes pass befor they are 2420 feet apart?

The first kid runs at a speed of 180 feet per minute, so he moves 180 feet away from the starting point every minute.

Similarly, the second kid runs at a speed of 120 feet per minute, so he moves 120 feet away from the starting point every minute.
Since they are running in opposite directions, their distance between them increases by 180 + 120 = 300 feet every minute.
To be 2420 feet apart, they need to be 2420 feet / 300 feet/minute = <<2420/300=8.066666666666666>>8.066666666666666 minutes apart.
Therefore, it takes approximately 8.066666666666666 minutes for them to be 2420 feet apart.

Please try again

Let's denote the time it takes for the kids to be 2420 feet apart as t minutes.

In t minutes, the first kid would have covered a distance of 180t feet, and the second kid would have covered a distance of 120t feet.

Since they are running in opposite directions, the total distance between them is the sum of the distances covered by each kid: 180t + 120t = 300t feet.

We want this to be equal to 2420 feet, so we can set up the equation:
300t = 2420

Solving for t, we divide both sides of the equation by 300:
t = 2420/300

Now, we can calculate the value of t:
t ≈ 8.07

Therefore, approximately 8.07 minutes pass before the kids are 2420 feet apart.

NO

Apologies for the confusion. Let's try solving the problem again.

The kids are initially 20 feet apart and moving in opposite directions. The combined speed at which they are moving apart is 180 + 120 = 300 feet per minute.

To determine how many minutes it takes for them to be 2420 feet apart, we can divide the total distance they need to cover by the rate at which they are moving apart:

2420 feet / 300 feet per minute = 8.07 minutes

Therefore, it takes approximately 8.07 minutes for the kids to be 2420 feet apart.

Please give me a different answer this time

Apologies for the confusion. Let's try solving the problem again.

The kids are initially 20 feet apart and moving in opposite directions. The combined speed at which they are moving apart is 180 + 120 = 300 feet per minute.

Every minute, the kids' distance increases by 300 feet. We want to find how many minutes it takes for them to reach a distance of 2420 feet.

To find the number of minutes, we divide 2420 feet by 300 feet per minute:

2420 feet / 300 feet per minute = 8.067 minutes

Therefore, it takes approximately 8.067 minutes for the kids to be 2420 feet apart.

NOOO! GIVE ME A COMPLETELY NEW ANSWER!!!!!!!!!!!!!!!!

Apologies for the confusion earlier. Let's solve the problem again.

The kids are initially 20 feet apart and moving in opposite directions. The combined rate at which they are moving apart is 180 + 120 = 300 feet per minute.

We need to determine the number of minutes it takes for the distance between them to reach 2420 feet.

Let's set up an equation:

20 + 300t = 2420

Simplifying the equation:

300t = 2400

Dividing both sides of the equation by 300:

t = 8

Therefore, it takes 8 minutes for the kids to be 2420 feet apart.

If one plane is flying 40 mph, and another plane is flying 100 mph, and they re 200 miles apart and flying directly towards each other, in how long will the planes meet?