You have 3.00 L of a 3.00 M solution of NaCl(aq) called solution A. You also have 2.00 L of a 2.00 M solution of AgNO3(aq) called solution B. You mix these solutions together, making solution C. Hint: AgCl is a precipitate.
Calculate the concentrations (in M) of the following ions in solution C.
Cl-
To find the concentration of Cl- in solution C, we need to consider the stoichiometry of the reaction between NaCl and AgNO3. The balanced chemical equation for this reaction is:
AgNO3(aq) + NaCl(aq) -> AgCl(s) + NaNO3(aq)
From this equation, we can see that 1 mole of AgNO3 reacts with 1 mole of NaCl to form 1 mole of AgCl. This means that the concentration of Cl- in solution C will be equal to the concentration of NaCl in solution A.
The concentration of NaCl in solution A is given as 3.00 M. Therefore, the concentration of Cl- in solution C will also be 3.00 M.