Find the surface area of a rectangular pyramid with these measurements: l = 8 cm, w = 4 cm, and h = 2 cm. Express your answer as a decimal rounded to the nearest hundredth
Its 72.52
To find the surface area of a rectangular pyramid, we need to find the area of the base and the area of each triangular face.
The area of the base is found by multiplying the length by the width: 8 cm * 4 cm = 32 cm^2.
The area of each triangular face is found by using the formula A = (1/2) * base * height, where the base is the length or width of the base and the height is the height of the pyramid.
For the first triangular face, the base is 8 cm and the height is 2 cm: A = (1/2) * 8 cm * 2 cm = 8 cm^2.
For the second triangular face, the base is 4 cm and the height is 2 cm: A = (1/2) * 4 cm * 2 cm = 4 cm^2.
For the third triangular face, the base is again 8 cm and the height is 2 cm: A = (1/2) * 8 cm * 2 cm = 8 cm^2.
For the fourth triangular face, the base is 4 cm and the height is 2 cm: A = (1/2) * 4 cm * 2 cm = 4 cm^2.
Now, we can add up the areas of the base and the faces to find the surface area of the pyramid:
32 cm^2 + 8 cm^2 + 4 cm^2 + 8 cm^2 + 4 cm^2 = 56 cm^2.
Rounded to the nearest hundredth, the surface area of the pyramid is 56.00 cm^2.