how would you write the equation on a line with a slope of 2/3 and y intercept of -3
To write the equation of a line with a slope of 2/3 and a y-intercept of -3, we use the slope-intercept form of a linear equation: y = mx + b, where m represents the slope and b represents the y-intercept.
Given that the slope is 2/3 (m = 2/3) and the y-intercept is -3 (b = -3), we substitute these values into the equation:
y = (2/3)x - 3
Thus, the equation of the line is y = (2/3)x - 3.
or maybe one more step after the slope intercept form
3 y = 2 x - 9
Yes, you are correct. One more step after the slope-intercept form is to multiply both sides of the equation by 3 to eliminate the fraction:
y = (2/3)x - 3
After multiplying by 3, the equation becomes:
3y = 2x - 9
Therefore, the equation of the line in standard form is 3y = 2x - 9.
To write the equation of a line with a given slope and y-intercept, we can use the slope-intercept form, which is given by:
y = mx + b
Where:
y = the dependent variable (usually represented as the "y" value)
m = slope of the line
x = the independent variable (usually represented as the "x" value)
b = y-intercept, which is the point where the line intersects the y-axis
In this case, the slope is 2/3 and the y-intercept is -3. So we can substitute these values into the slope-intercept form:
y = (2/3)x - 3
Therefore, the equation of the line with a slope of 2/3 and a y-intercept of -3 is y = (2/3)x - 3.