complete the equation og the line throught (-9,-9) and (-6,0)
To find the equation of the line passing through the points (-9, -9) and (-6, 0), we can use the slope-intercept form of a linear equation, which is y = mx + b.
First, let's find the slope (m) of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Where (x1, y1) = (-9, -9) and (x2, y2) = (-6, 0).
m = (0 - (-9)) / (-6 - (-9))
m = 9 / 3
m = 3
Now that we have the slope, we can substitute it into the equation y = mx + b, along with one of the points to find the y-intercept (b).
Using (-6, 0):
0 = 3(-6) + b
0 = -18 + b
b = 18
So, the equation of the line passing through (-9, -9) and (-6, 0) is:
y = 3x + 18