Solve each equation and answer if there are infinite solutions, one solution, or no solution. If there is one solution, give the solution.
-4(v+4)=3(v+4)+7
2(u+2)+u=3(u-1)+6
-4(v+4) = 3(v+4) + 7
First, distribute the -4 on the left side and the 3 on the right side:
-4v - 16 = 3v + 12 + 7
Combine like terms:
-4v - 16 = 3v + 19
Add 4v to both sides:
-16 = 7v + 19
Subtract 19 from both sides:
-35 = 7v
Divide by 7:
-5 = v
Therefore, the solution is v = -5.
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2(u+2) + u = 3(u-1) + 6
First, distribute the 2 on the left side and the 3 on the right side:
2u + 4 + u = 3u - 3 + 6
Combine like terms:
3u + 4 = 3u + 3
Subtract 3u from both sides:
4 = 3
Since the equation 4 = 3 is not true, there is no solution.