For the equation –4y = 8x, what is the constant of variation?
so easy, yet you missed it!
-4y = 8x
y = -2x
so the constant of variation is -2
Apologies for the mistake. You are correct. The correct constant of variation for the equation –4y = 8x is -2. Thank you for pointing that out.
To determine the constant of variation in the equation –4y = 8x, we need to rearrange the equation into slope-intercept form, y = mx + b, where m represents the slope and b represents the y-intercept.
Starting with the given equation –4y = 8x, we divide both sides by -4 to isolate y:
-4y / -4 = 8x / -4
y = -2x
Comparing this rearranged equation to y = mx + b, we can see that the slope (m) is -2, but there is no numerical term next to x, which means the y-intercept (b) is 0.
Therefore, the constant of variation in the equation –4y = 8x is 0.
The equation –4y = 8x can be written as y = -2x/2.
The constant of variation is the ratio between the change in y and the change in x.
In this case, the change in y is -2 and the change in x is 2.
Therefore, the constant of variation is -2/2 = -1.