A bag contains the following prize tickets: • 6 tickets labeled “8-ounce bottle of SLIME” • 2 tickets labeled “4 RINGTONES” • 8 tickets labeled “32-ounce SLUSHIE” • 4 tickets labeled “16-ounce ICE CREAM SUNDAE”. Each of the 190 7th grade students who passed the Math benchmark test will draw a prize ticket from the bag. The prize will be recorded for that student, then the ticket will be returned to the bag. What is a reasonable prediction for the number of times a slushie or an ice cream sundae prize ticket will be drawn? Responses A 7676 B 3838 C 104104 D 114
To predict the number of times a slushie or an ice cream sundae prize ticket will be drawn, we need to add the number of slushie prize tickets and the number of ice cream sundae prize tickets.
There are 8 slushie prize tickets and 4 ice cream sundae prize tickets.
Adding them together gives us 8 + 4 = 12.
Therefore, a reasonable prediction for the number of times a slushie or an ice cream sundae prize ticket will be drawn is 12.
Therefore, the correct answer is not listed among the given options.
you sure?
Apologies for the confusion. Let's try to calculate the number of times a slushie or an ice cream sundae prize ticket will be drawn.
The bag contains a total of (6+2+8+4) = 20 prize tickets.
Out of these, the slushie prize tickets and ice cream sundae prize tickets add up to (8+4) = 12.
Since there are 190 students, and each will draw a ticket, the probability of drawing a slushie or an ice cream sundae ticket can be calculated as (12/20) = 0.6.
The expected number of times a slushie or an ice cream sundae ticket will be drawn can be calculated by multiplying the probability by the total number of students: 0.6 * 190 = 114.
Therefore, a reasonable prediction for the number of times a slushie or an ice cream sundae prize ticket will be drawn is 114.
Hence, the correct answer is D) 114.
The College of Veterinary Medicine at Texas A&M University conducted a study of the rattlesnake vaccine for dogs. The researchers determined that: •12 out of 15 cases of dogs that received the vaccine prior to the rattlesnake bite survived, and •8 out of 18 cases of dogs who did not receive the vaccine prior to the rattlesnake bite survived. If there were 900 dogs in the study that received the vaccine and were then bitten by a rattlesnake, how many of this group did NOT survive the rattlesnake bite? Responses A 720720 B 400400 C 180180 D 500
From the given information, we know that 12 out of 15 dogs that received the vaccine prior to the rattlesnake bite survived. This means that 15 - 12 = 3 dogs did not survive.
Since there were 900 dogs in the study that received the vaccine, we can calculate the number of dogs that did not survive by multiplying the ratio of dogs that did not survive (3/15) by the total number of dogs that received the vaccine (900).
Number of dogs that did not survive = (3/15) * 900 = 180.
Therefore, out of the group of dogs that received the vaccine and were bitten by a rattlesnake, 180 did not survive the rattlesnake bite.
Hence, the correct answer is C) 180180.
Which two expressions are equivalent to 7(t + 5)? Responses A (5 + t) • 7(5 + t ) • 7 B 7 • 5 + 7 • t7 • 5 + 7 • t C 5(t + 7)5( t + 7) D 7 • 5 • t7 • 5 • t E 7 • 5 + t
To find the expressions that are equivalent to 7(t + 5), we can distribute the 7 to both the terms inside the parentheses.
Distributing the 7, we get: 7t + 7(5).
Simplifying further, we have: 7t + 35.
Therefore, the two expressions that are equivalent to 7(t + 5) are:
B) 7 • 5 + 7 • t
and
E) 7 • 5 + t.
Hence, the correct answer is B) 7 • 5 + 7 • t and E) 7 • 5 + t.
you sure
Apologies for the mistake. Let's go through the expressions again.
The expression 7(t + 5) can be distributed as 7t + 7(5).
Simplifying further, we have 7t + 35.
Therefore, the two expressions that are equivalent to 7(t + 5) are:
B) 7 • 5 + 7 • t
and
E) 7 • 5 + t.
Hence, the correct answer is B) 7 • 5 + 7 • t and E) 7 • 5 + t.