An Australian emu is running due north in a straight line at a speed of 1.30m/s and slow down to a speed pf 9.50 m/s in 4.70s. (a) what is the magnitude and direction of the birds acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.70s has elapsed?
(a) To find the magnitude of the bird's acceleration, we need to calculate the change in its velocity over time:
Initial velocity (u) = 1.30 m/s
Final velocity (v) = 9.50 m/s
Time (t) = 4.70 s
Acceleration (a) = (v - u) / t
= (9.50 - 1.30) / 4.70
= 8.20 / 4.70
= 1.7447 m/s²
The magnitude of the bird's acceleration is 1.7447 m/s².
Since the bird is slowing down, its acceleration is opposite to its initial direction. So, the direction of the bird's acceleration is south.
(b) To find the bird's velocity after an additional 1.70s has elapsed, we can use the equation:
Final velocity (v) = initial velocity (u) + (acceleration × time)
Initial velocity (u) = 9.50 m/s (since we're considering the bird's velocity after it has slowed down)
Acceleration (a) = 1.7447 m/s²
Time (t) = 1.70 s
v = 9.50 + (1.7447 × 1.70)
≈ 12.76 m/s
Therefore, the bird's velocity after an additional 1.70s has elapsed is approximately 12.76 m/s.