The area of a rectangle is 220 square centimeters. If the perimeter is 62 centimeters, find the length and width of the rectangle.
Let L be the length and W be the width of the rectangle.
LW = 220 inches²......(Equation 1)
2L + 2W = 62 inches.....(Equation 2)
Multiply Equation 1 by 2: 2LW = 440 inches².......(Equation 3)
From Equation 2, solve for L: 2L = 62 - 2W
L = (62 - 2W) / 2
Substitute L in Equation 3: (62 - 2W)W = 440
62W - 2W² = 440
Rearrange the equation: 2W² - 62W + 440 = 0
Factor: (2W - 20)(W - 22) = 0
So, W = 20 cm or W = 22 cm.
But if W = 22 cm, then L = (62 - 2(22)) / 2 = 62 - 44 = 18 cm.
So, the width is 18 cm and the length is 22 cm. Answer: \boxed{18, \ 22}.