If log 2=0.3010,log 3=0.4771 and log 5=0.6990 find log 36
To find log 36, we can use the property of logarithms that states log A + log B = log (A * B).
Since 36 is the product of two prime numbers, we can express it as 36 = 4 * 9 = 2^2 * 3^2.
Therefore, log 36 = log(2^2 * 3^2)
Using the property mentioned above, we can rewrite this equation as:
log 36 = log 2^2 + log 3^2
Now, we can use the given logarithms to calculate log 2^2 and log 3^2.
log 2^2 = 2 * log 2 = 2 * 0.3010 = 0.6020
log 3^2 = 2 * log 3 = 2 * 0.4771 = 0.9542
Now, we can substitute these values back into the original equation:
log 36 = log 2^2 + log 3^2 = 0.6020 + 0.9542 = 1.5562
Therefore, log 36 = 1.5562.