Cody and Ndiba each improved their yards by planting hostas and geraniums. They bought their supplies from the same store. Cody spent $28 on 2 hostas and 3 geraniums. Ndiba spent $16 on 2 hostas and 1 geranium.
Find the cost of one hosta and one geranium.
Let the cost of one hosta be h and let the cost of one geranium be g.
From the problem, we know that Cody spent $28 on 2 hostas and 3 geraniums, so we can write the equation:
2h + 3g = 28
Similarly, we know that Ndiba spent $16 on 2 hostas and 1 geranium, so we can write the equation:
2h + 1g = 16
We can now solve this system of equations to find the values of h and g.
First, we can multiply the second equation by 3 to eliminate g when we add the equations:
3 * (2h + 1g) = 3 * 16
6h + 3g = 48
Now, we can subtract this equation from the first equation to eliminate g:
(2h + 3g) - (6h + 3g) = 28 - 48
2h + 3g - 6h - 3g = -20
-4h = -20
h = -20 / -4
h = 5
Now that we have the value of h, we can substitute it into either of the original equations to find the value of g. Let's use the second equation:
2 * 5 + 1g = 16
10 + g = 16
g = 16 - 10
g = 6
Therefore, the cost of one hosta is $5 and the cost of one geranium is $6.