Divide -3x^(3)-4x^(2)+4x+3 by x-2.
To divide \( -3x^3 -4x^2 +4x +3 \) by \( x-2 \), we can use long division.
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x - 2 | -3x^3 - 4x^2 + 4x + 3
-3x^3 + 6x^2
_____________
- 10x^2 + 4x + 3
- 10x^2 + 20x
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- 16x + 3
- 16x + 32
_____________
-29
Hence, the quotient is \( -3x^2 + 6x - 16 \) and the remainder is -29.