How much air is needed to fill a basketball with a diameter of 9 inches? Use 3.14 as an approximation for pl. Round your answer to the nearest tenth. (1 point) 190.8in .^ 3; 113in .^ 3; 381.5in .^ 3; 3.052 * 0.1in .^ 3
The volume of a sphere is given by the formula V = (4/3) * π * r^3, where r is the radius of the sphere.
Since the diameter of the basketball is 9 inches, the radius would be half of that, which is 4.5 inches.
Substituting the values into the formula:
V = (4/3) * 3.14 * (4.5^3)
= 4.189 * 91.125
≈ 381.5in^3
Therefore, the amount of air needed to fill the basketball is approximately 381.5in^3.