Which of the following is a point on the graph as described by the function y = (2x + 1)² - 4? (1 point) O (-1, -3) O (-1,-5) O (1,2) (0, -2)
To find a point on the graph of the function, we can choose a value for x and substitute it into the equation to solve for y.
Let's try the point (-1, -3) first:
y = (2(-1) + 1)² - 4
y = ( -2 + 1 )² - 4
y = ( -1 )² - 4
y = 1 - 4
y = -3
So, (-1, -3) is a point on the graph of the function.
We can also check the other points:
For (-1, -5):
y = (2(-1) + 1)² - 4
y = ( -2 + 1 )² - 4
y = ( -1 )² - 4
y = 1 - 4
y = -3
(-1, -5) is not a point on the graph.
For (1, 2):
y = (2(1) + 1)² - 4
y = ( 2 + 1 )² - 4
y = ( 3 )² - 4
y = 9 - 4
y = 5
(1, 2) is not a point on the graph.
For (0, -2):
y = (2(0) + 1)² - 4
y = ( 0 + 1 )² - 4
y = ( 1 )² - 4
y = 1 - 4
y = -3
(0, -2) is not a point on the graph.
Therefore, the point (-1, -3) is on the graph as described by the function y = (2x + 1)² - 4.