2.0 kg block is pushed 1.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 28.0° with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s?
Your
28°
2 kg
Drawing not to scale.
If the coefficient of kinetic friction between the block and the wall is 0.20, find
c) the magnitude of the normal force between the block and the wall
To find the magnitude of the normal force between the block and the wall, we need to consider the forces acting on the block.
1. Gravity: The force of gravity acts vertically downwards with a magnitude of 2.0 kg * 9.81 m/s^2 = 19.62 N.
2. Normal force: The normal force acts perpendicular to the surface of the wall and counteracts the force of gravity. Since the block is moving up the wall at a constant velocity, the normal force must be equal in magnitude to the gravitational force, so the normal force is also 19.62 N.
3. Friction force: The friction force acts parallel to the surface of the wall and opposes the motion of the block. The magnitude of the friction force can be found using the formula: friction force = coefficient of friction * normal force. Given that the coefficient of kinetic friction is 0.20 and the normal force is 19.62 N, the friction force is 0.20 * 19.62 N = 3.924 N.
In summary, the magnitude of the normal force between the block and the wall is 19.62 N.