Use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2 inches. Use 3.14 as an approximation for pi and round your answer to the nearest hundredth, if necessary.(1 point) Responses 1,222.54 in.3 1,222.54 in cubed 3,260.11 in.3 3,260.11 inches cubed 407.51 in.3 407.51 inches cubed 115.55 in.3
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere. Since the diameter of the basketball is 9.2 inches, the radius (r) is half of that, which is 4.6 inches.
Plugging in the value of r into the formula:
V = (4/3)(3.14)(4.6^3)
V = (4/3)(3.14)(97.336)
V ≈ 407.51 cubic inches
Therefore, the volume of the basketball is approximately 407.51 cubic inches.
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere. In this case, the radius is 1.8 yards.
Plugging in the value of r into the formula:
V = (4/3)π(1.8^3)
V = (4/3)π(5.832)
V = 7.776π
Rounding to the nearest hundredth:
V ≈ 7.78π cubic yards
Therefore, the volume of the sphere with a radius of 1.8 yards is approximately 7.78π cubic yards.
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere.
Given that the diameter of the basketball is 9 inches, the radius (r) is half of that, which is 4.5 inches.
Plugging in the value of r into the formula:
V = (4/3)(3.14)(4.5^3)
V = (4/3)(3.14)(91.125)
V ≈ 381.6 cubic inches
Therefore, approximately 381.6 cubic inches of air is needed to fill the basketball. Rounding to the nearest tenth, the answer is 381.5 cubic inches.
1-4 are correct but you got number 5 wrong it was 9,682 in
Find the volume of a sphere with a radius of 1.8 yards. Leave your answer in terms of pi. Round your answer to the nearest hundredth, if necessary.(1 point) Responses 23.34π yds3 23.34 pi yds cubed 7.2π yds3 7.2 pi yds cubed 24.43π yds3 24.43 pi yds cubed 7.78π yds3 7.78 pi yds cubed
Use the formula for the volume of a sphere to solve the following problem. How much air is needed to fill a basketball with a diameter of 9 inches? Use 3.14 as an approximation for pi. Round your answer to the nearest tenth. (1 point) Responses 3,052.1 in.3 3,052.1 inches cubed 113 in.3 113 inches cubed 381.5 in.3 381.5 inches cubed 190.8 in.3
The volume of a container measures 4,000 mm3 and contains 50 marbles. Each marble has a radius of 2 mm. Use 3.14 as an approximation for pi. How much space in the box is unused? Round your answer to the nearest tenth.(1 point) Responses 3,900 mm3 3,900 mm cubed 1,674.7 mm3 1,674.7 mm cubed 33.5 mm3 33.5 mm cubed 2,325.3 mm3
The volume of the container is 4,000 mm^3. Each marble has a radius of 2 mm.
The volume of one marble can be calculated using the formula for the volume of a sphere: V = (4/3)πr^3, where r is the radius of the sphere.
Plugging in the value of r into the formula:
V = (4/3)(3.14)(2^3)
V = (4/3)(3.14)(8)
V = 33.4933 mm^3 (rounded to the nearest tenth)
Multiplying the volume of one marble by the number of marbles:
Total volume of marbles = 33.4933 mm^3 * 50 = 1,674.665 mm^3 (rounded to the nearest tenth)
Therefore, the space unused in the box is approximately 2,325.3 mm^3 (4,000 mm^3 - 1,674.665 mm^3) when rounded to the nearest tenth.
Kairay created a sculpture by forming a hemisphere with a radius of 20 inches and then removing a hemisphere with a radius of 15 inches from it. Calculate the volume of his sculpture. Use 3.14 as an approximation for pi. Round your answer to the nearest whole number.(1 point) Responses 9,682 in.3 9,682 inches cubed 19,363 in.3 19,363 inches cubed 16,747 in.3 16,747 inches cubed 7,065 in.3 7,065 inches cubed
The volume of a hemisphere can be calculated using the formula V = (2/3)πr^3, where r is the radius of the hemisphere.
First, we will calculate the volume of the larger hemisphere:
V1 = (2/3)(3.14)(20^3)
V1 = (2/3)(3.14)(8,000)
V1 ≈ 33,493.33 cubic inches
Next, we will calculate the volume of the smaller hemisphere:
V2 = (2/3)(3.14)(15^3)
V2 = (2/3)(3.14)(3,375)
V2 ≈ 14,130 cubic inches
To find the volume of the sculpture, we subtract the volume of the smaller hemisphere from the volume of the larger hemisphere:
Volume of sculpture = V1 - V2
Volume of sculpture ≈ 33,493.33 - 14,130
Volume of sculpture ≈ 19,363.33 cubic inches
Rounding to the nearest whole number, the volume of Kairay's sculpture is approximately 19,363 cubic inches.